What is expand ((x^{2(2n+1)}+3^{2n+1}))/7 ?

The solution to expand ((x^{2(2n+1)}+3^{2n+1}))/7 is (x^{4n+2})/7+(3^{2n+1})/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x^{2(2n+1)}+3^{2n+1}))/7

expand

\frac{( x ^{2 (2 n + 1)} + 3 ^{2 n + 1} )}{7}

\frac{x ^{4 n + 2}}{7} + \frac{3 ^{2 n + 1}}{7}

Solution steps

\frac{x ^{2 (2 n + 1)} + 3 ^{2 n + 1}}{7}

Expand

2 (2 n + 1) : 4 n + 2

= \frac{x ^{4 n + 2} + 3 ^{2 n + 1}}{7}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4 n + 2} + 3 ^{2 n + 1}}{7} = \frac{x ^{4 n + 2}}{7} + \frac{3 ^{2 n + 1}}{7}

= \frac{x ^{4 n + 2}}{7} + \frac{3 ^{2 n + 1}}{7}

\frac{1}{x ^{2} ( x + 5 )}

\frac{2}{( x - 2 ) ( x + 1 ) ^{2}}

2 (4 π + \frac{3}{4})

\frac{3}{x + 2} - \frac{2}{3 x - 1} - \frac{4}{( 3 x - 1 ) ^{2}}

e^{x} (e^{x} + x \cdot e^{x})

What is expand ((x^{2(2n+1)}+3^{2n+1}))/7 ?
The solution to expand ((x^{2(2n+1)}+3^{2n+1}))/7 is (x^{4n+2})/7+(3^{2n+1})/7