What is expand ((x+3)^2)/((x-1)^2+4a) ?

The solution to expand ((x+3)^2)/((x-1)^2+4a) is (x^2+6x+9)/(x^2-2x+1+4a)

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expand ((x+3)^2)/((x-1)^2+4a)

expand

\frac{( x + 3 ) ^{2}}{( x - 1 ) ^{2} + 4 a}

\frac{x ^{2} + 6 x + 9}{x ^{2} - 2 x + 1 + 4 a}

Solution steps

\frac{( x + 3 ) ^{2}}{( x - 1 ) ^{2} + 4 a}

(x + 3)^{2} = x^{2} + 6 x + 9

= \frac{x ^{2} + 6 x + 9}{( x - 1 ) ^{2} + 4 a}

Expand

(x - 1)^{2} + 4 a : x^{2} - 2 x + 1 + 4 a

= \frac{x ^{2} + 6 x + 9}{x ^{2} - 2 x + 1 + 4 a}

(x - 1)^{- 1} - (x + 3)^{- 1}

(2 x^{2} - 5 π x - 3) (x^{2} - 2 x + e)

(x - 2) \cdot \frac{d}{d x} (1 - 4 4 - x^{2})

- \frac{2 l ( ( - 1 ) ^{n} - 1 )}{π ^{2} n ^{2}}

What is expand ((x+3)^2)/((x-1)^2+4a) ?
The solution to expand ((x+3)^2)/((x-1)^2+4a) is (x^2+6x+9)/(x^2-2x+1+4a)