What are the solutions to the equation x^2+(10-2x)^2=25 ?

The solutions to the equation x^2+(10-2x)^2=25 are x=5,x=3

Find the zeros of x^2+(10-2x)^2=25

The zeros of x^2+(10-2x)^2=25 are x=5,x=3

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x^{2} + (10 - 2 x)^{2} = 25

x = 5, x = 3

Solution steps

x^{2} + (10 - 2 x)^{2} = 25

Expand

x^{2} + (10 - 2 x)^{2} : 5 x^{2} - 40 x + 100

5 x^{2} - 40 x + 100 = 25

Move

25

to the left side

5 x^{2} - 40 x + 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 5 \cdot 75}{2 \cdot 5}

(- 40)^{2} - 4 \cdot 5 \cdot 75 = 10

x_{1, 2} = \frac{- ( - 40 ) \pm 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 10}{2 \cdot 5}, x_{2} = \frac{- ( - 40 ) - 10}{2 \cdot 5}

x = \frac{- ( - 40 ) + 10}{2 \cdot 5} : 5

x = \frac{- ( - 40 ) - 10}{2 \cdot 5} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

2.02 x + 4.8 = 14.782 - 1.2 x

- \frac{r}{3} = - 7

21 + n \geq 5

\frac{3}{3 + 5}

\frac{( x - 4 ) ( x + 3 )}{( x - 6 ) ( x + 7 )} \geq 0

What are the solutions to the equation x^2+(10-2x)^2=25 ?
The solutions to the equation x^2+(10-2x)^2=25 are x=5,x=3
Find the zeros of x^2+(10-2x)^2=25
The zeros of x^2+(10-2x)^2=25 are x=5,x=3