What is expand (x^2-4x)dx1.3^' ?

The solution to expand (x^2-4x)dx1.3^' is 1.3^'x^2dx-4*1.3^'xdx

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expand (x^2-4x)dx1.3^'

expand

(x^{2} - 4 x) d x 1. 3^{^{'}}

1. 3^{'} x^{2} d x - 4 \cdot 1. 3^{'} x d x

Solution steps

(x^{2} - 4 x) d x \cdot 1. 3^{^{'}}

= 1. 3^{^{^{'}}} (x^{2} - 4 x) d x

Apply the distributive law:

a (b - c) = ab - a c

a = d x \cdot 1. 3^{^{'}}, b = x^{2}, c = 4 x

= d x \cdot 1. 3^{^{^{'}}} x^{2} - d x \cdot 1. 3^{^{^{'}}} \cdot 4 x

= 1. 3^{^{^{'}}} x^{2} d x - 4 \cdot 1. 3^{^{^{'}}} x d x

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What is expand (x^2-4x)dx1.3^' ?
The solution to expand (x^2-4x)dx1.3^' is 1.3^'x^2dx-4*1.3^'xdx