What is expand x^{n+1}(x^n+3)+x^n(x^3-1)' ?

The solution to expand x^{n+1}(x^n+3)+x^n(x^3-1)' is x^{2n+1}+3x^{n+1}+x^n(x^3-1)'

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expand x^{n+1}(x^n+3)+x^n(x^3-1)'

expand

x^{n + 1} (x^{n} + 3) + x^{n} (x^{3} - 1)^{'}

x^{2 n + 1} + 3 x^{n + 1} + x^{n} (x^{3} - 1)'

Solution steps

x^{n + 1} (x^{n} + 3) + x^{n} (x^{3} - 1)^{'}

Expand

x^{n + 1} (x^{n} + 3) : x^{2 n + 1} + 3 x^{n + 1}

= x^{2 n + 1} + 3 x^{n + 1} + x^{n} (x^{3} - 1)^{'}

\frac{n ^{2} + 2 n - 8}{16 ( n + 3 )}

\frac{( x ^{2} - 8 ) ^{2}}{2}

t^{4} (e^{\frac{11}{3}} + t^{2})

(x + 5 y = - 15) \cdot (- 1)

- \frac{j}{( 1 - 2 j ) \cdot ( 1 + 2 j )}

What is expand x^{n+1}(x^n+3)+x^n(x^3-1)' ?
The solution to expand x^{n+1}(x^n+3)+x^n(x^3-1)' is x^{2n+1}+3x^{n+1}+x^n(x^3-1)'