What is expand n*ln(n)-n-(n+1)ln(x) ?

The solution to expand n*ln(n)-n-(n+1)ln(x) is nln(n)-n-nln(x)-ln(x)

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expand n*ln(n)-n-(n+1)ln(x)

expand

n \cdot ln (n) - n - (n + 1) ln (x)

n ln (n) - n - n ln (x) - ln (x)

Solution steps

n ln (n) - n - (n + 1) ln (x)

= n ln (n) - n - ln (x) (n + 1)

Expand

- ln (x) (n + 1) : - n ln (x) - ln (x)

= n ln (n) - n - n ln (x) - ln (x)

(x - 1) \cdot (3 x^{4} = 7 x^{3} + 3 x^{2} + 3 x - 2)

\frac{( x + 4 ) ( x - 27 )}{( x ^{2} + 12 x + 37 ) ( x + 3 )}

\frac{x + 3}{( x - 1 ) ^{2}}

\frac{2 x ( 5 - x )}{25 ( x - 2 )}

\frac{( ( x + 2 ) ( 2 a + 1 + x ) )}{2}

What is expand n*ln(n)-n-(n+1)ln(x) ?
The solution to expand n*ln(n)-n-(n+1)ln(x) is nln(n)-n-nln(x)-ln(x)