What is expand (5i^9(2-3i))/(2-1) ?

The solution to expand (5i^9(2-3i))/(2-1) is 15+10i

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expand (5i^9(2-3i))/(2-1)

expand

\frac{5 i ^{9} ( 2 - 3 i )}{2 - 1}

15 + 10 i

Solution steps

\frac{5 i ^{9} ( 2 - 3 i )}{2 - 1}

Subtract the numbers:

2 - 1 = 1

= \frac{5 i ^{9} ( 2 - 3 i )}{1}

Apply rule

\frac{a}{1} = a

= 5 i^{9} (2 - 3 i)

i^{9} = i

= 5 i (2 - 3 i)

Apply complex arithmetic rule:

(ai) (b + c i) = - a c + abi

a = 5, b = 2, c = - 3

= - 5 (- 3) + 5 \cdot 2 i

- 5 (- 3) = 15

5 \cdot 2 = 10

= 15 + 10 i

\frac{( ( x + 3 ) ^{2} ( 2 x - 3 ) )}{( x + 1 ) ^{2}}

\frac{- 2 x ^{2} + x - 2}{x ^{2} ( x - 2 ) ( x ^{2} + 1 )}

d t (3 t^{4} - 5 t^{6})

(1 + e^{f (x)})^{2}

\frac{2 ( 55 - 15 )}{5}

What is expand (5i^9(2-3i))/(2-1) ?
The solution to expand (5i^9(2-3i))/(2-1) is 15+10i