What is expand ((t^3+1)(t^2-1))/2 ?

The solution to expand ((t^3+1)(t^2-1))/2 is (t^5)/2-(t^3)/2+(t^2)/2-1/2

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expand ((t^3+1)(t^2-1))/2

expand

\frac{( t ^{3} + 1 ) ( t ^{2} - 1 )}{2}

\frac{t ^{5}}{2} - \frac{t ^{3}}{2} + \frac{t ^{2}}{2} - \frac{1}{2}

Solution steps

\frac{( t ^{3} + 1 ) ( t ^{2} - 1 )}{2}

Expand

(t^{3} + 1) (t^{2} - 1) : t^{5} - t^{3} + t^{2} - 1

= \frac{t ^{5} - t ^{3} + t ^{2} - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{t ^{5} - t ^{3} + t ^{2} - 1}{2} = \frac{t ^{5}}{2} - \frac{t ^{3}}{2} + \frac{t ^{2}}{2} - \frac{1}{2}

= \frac{t ^{5}}{2} - \frac{t ^{3}}{2} + \frac{t ^{2}}{2} - \frac{1}{2}

\frac{160}{100 - \frac{1}{5}}

\frac{1}{s ^{2} ( x \cdot s + y )}

(- x + 2 + sy (x, s) = 1) \cdot s

\frac{d}{d y} ((x) (1 - e^{- x} - e^{- y} + e^{- x - y}))

(t (2 - t)) \cdot 2

What is expand ((t^3+1)(t^2-1))/2 ?
The solution to expand ((t^3+1)(t^2-1))/2 is (t^5)/2-(t^3)/2+(t^2)/2-1/2