What is expand (5x^2-4+7)-(3x^2=7x-1) ?

The solution to expand (5x^2-4+7)-(3x^2=7x-1) is 2x^2+3=7x+1

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expand (5x^2-4+7)-(3x^2=7x-1)

expand

(5 x^{2} - 4 + 7) - (3 x^{2} = 7 x - 1)

2 x^{2} + 3 = 7 x + 1

Solution steps

(5 x^{2} - 4 + 7) - (3 x^{2} = 7 x - 1)

= (5 x^{2} - 4 + 7) - (3 \cdot 7 = x^{2} x - 1)

- (3 x^{2} = 7 x - 1) : - 3 x^{2} = 7 x + 1

(5 x^{2} - 4 + 7) - 3 x^{2} = 7 x + 1

Expand

(5 x^{2} - 4 + 7) - 3 x^{2} : 2 x^{2} + 3

2 x^{2} + 3 = 7 x + 1

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What is expand (5x^2-4+7)-(3x^2=7x-1) ?
The solution to expand (5x^2-4+7)-(3x^2=7x-1) is 2x^2+3=7x+1