What is expand (3x+1)((x+2))/((x-1=0)) ?

The solution to expand (3x+1)((x+2))/((x-1=0)) is 3*((x+2))/((x-1*0=))x+1*((x+2))/((x-1*0=))

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expand (3x+1)((x+2))/((x-1=0))

expand

(3 x + 1) \frac{( x + 2 )}{( x - 1 = 0 )}

3 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )} x + 1 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )}

Solution steps

(3 x + 1) \frac{( x + 2 )}{( x - 1 = 0 )}

= \frac{( x + 2 )}{( x - 1 \cdot 0 = )} (3 x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{( x + 2 )}{( x - 1 = 0 )}, b = 3 x, c = 1

= \frac{( x + 2 )}{( x - 1 = 0 )} \cdot 3 x + \frac{( x + 2 )}{( x - 1 = 0 )} \cdot 1

= 3 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )} x + 1 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )}

\frac{4 + x}{3 1 - 2 x}

(x + y) e^{- x^{2} - y^{2}}

(4 z + x^{2} z) d z + (1 + z^{2}) x d x - (y z^{2} + y) (4 + x^{2}) d y

\frac{d}{d x} (y (x + y + 1)) + \frac{d}{d y} (x + 2 y)

(x^{3} + y^{3}) d x + (3 x y^{2} + 2) d y

What is expand (3x+1)((x+2))/((x-1=0)) ?
The solution to expand (3x+1)((x+2))/((x-1=0)) is 3*((x+2))/((x-1*0=))x+1*((x+2))/((x-1*0=))