What is expand (u^4(7y^5-9))/(3y^4) ?

The solution to expand (u^4(7y^5-9))/(3y^4) is (7u^4y)/3-(3u^4)/(y^4)

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expand (u^4(7y^5-9))/(3y^4)

expand

\frac{u ^{4} ( 7 y ^{5} - 9 )}{3 y ^{4}}

\frac{7 u ^{4} y}{3} - \frac{3 u ^{4}}{y ^{4}}

Solution steps

\frac{u ^{4} ( 7 y ^{5} - 9 )}{3 y ^{4}}

Expand

u^{4} (7 y^{5} - 9) : 7 u^{4} y^{5} - 9 u^{4}

= \frac{7 u ^{4} y ^{5} - 9 u ^{4}}{3 y ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{7 u ^{4} y ^{5} - 9 u ^{4}}{3 y ^{4}} = \frac{7 u ^{4} y ^{5}}{3 y ^{4}} - \frac{9 u ^{4}}{3 y ^{4}}

= \frac{7 u ^{4} y ^{5}}{3 y ^{4}} - \frac{9 u ^{4}}{3 y ^{4}}

Cancel

\frac{7 u ^{4} y ^{5}}{3 y ^{4}} : \frac{7 u ^{4} y}{3}

= \frac{7 u ^{4} y}{3} - \frac{9 u ^{4}}{3 y ^{4}}

Divide the numbers:

\frac{9}{3} = 3

= \frac{7 u ^{4} y}{3} - \frac{3 u ^{4}}{y ^{4}}

10000 e^{0.25 (t - 1.25)^{2}}

\frac{3 x + 4}{12 c ^{2} m ^{16} ( 4 x + 3 )}

p_{1} (p^{1} = 3.25 + \frac{1}{4} p_{1})

- (\frac{6}{9} (+) + (- \frac{8}{6})) + (- 1 \frac{1}{12} - 1.25) + 3^{0}

(4.47 + 0.09 i) ln (- 3 + i)

What is expand (u^4(7y^5-9))/(3y^4) ?
The solution to expand (u^4(7y^5-9))/(3y^4) is (7u^4y)/3-(3u^4)/(y^4)