What are the solutions to the equation -4x^2+3x=-1 ?

The solutions to the equation -4x^2+3x=-1 are x=-1/4 ,x=1

Find the zeros of -4x^2+3x=-1

The zeros of -4x^2+3x=-1 are x=-1/4 ,x=1

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- 4 x^{2} + 3 x = - 1

x = - \frac{1}{4}, x = 1

Decimal Notation

x = - 0.25, x = 1

Solution steps

- 4 x^{2} + 3 x = - 1

Move

1

to the left side

- 4 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 1}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 1 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 ( - 4 )}, x_{2} = \frac{- 3 - 5}{2 ( - 4 )}

x = \frac{- 3 + 5}{2 ( - 4 )} : - \frac{1}{4}

x = \frac{- 3 - 5}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = 1

1 + ln (1)

\frac{5}{2 x} < 0

- (\frac{3}{2})^{1}

x^{3} + 6 x^{2} - 40 x

\frac{( - 5 ) ^{5}}{( - 5 ) ^{- 6}}

What are the solutions to the equation -4x^2+3x=-1 ?
The solutions to the equation -4x^2+3x=-1 are x=-1/4 ,x=1
Find the zeros of -4x^2+3x=-1
The zeros of -4x^2+3x=-1 are x=-1/4 ,x=1