What is expand cos(2x)-sin(2x)(pi/4+3pi) ?

The solution to expand cos(2x)-sin(2x)(pi/4+3pi) is cos(2x)-pi/4 sin(2x)-3pisin(2x)

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expand cos(2x)-sin(2x)(pi/4+3pi)

expand

cos (2 x) - sin (2 x) (\frac{π}{4} + 3 π)

cos (2 x) - \frac{π}{4} sin (2 x) - 3 π sin (2 x)

Solution steps

cos (2 x) - sin (2 x) (\frac{π}{4} + 3 π)

= cos (2 x) - (\frac{π}{4} + 3 π) sin (2 x)

Expand

- sin (2 x) (\frac{π}{4} + 3 π) : - \frac{π}{4} sin (2 x) - 3 π sin (2 x)

= cos (2 x) - \frac{π}{4} sin (2 x) - 3 π sin (2 x)

\frac{( m + 3 ) ( m - 3 )}{m ^{2} - 16}

\frac{( e ^{x} - 1 ) ( e ^{2 y} - 1 )}{x y}

\frac{15 ( s + 20 )}{15 s ^{3} + s + 1}

x (x - 1) y^{''} (x) + 6 x^{2} y^{'} (x) + 3 y

(315 + 5) x

What is expand cos(2x)-sin(2x)(pi/4+3pi) ?
The solution to expand cos(2x)-sin(2x)(pi/4+3pi) is cos(2x)-pi/4 sin(2x)-3pisin(2x)