What is expand (t+1)*(df)/(dt) ?

The solution to expand (t+1)*(df)/(dt) is t(df)/(dt)+(df)/(dt)

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expand (t+1)*(df)/(dt)

expand

(t + 1) \cdot \frac{df}{d t}

t \frac{df}{d t} + \frac{df}{d t}

Solution steps

(t + 1) \frac{df}{d t}

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{df}{d t}, b = t, c = 1

= \frac{df}{d t} t + \frac{df}{d t} 1

= t \frac{df}{d t} + 1 \frac{df}{d t}

Multiply:

1 \frac{df}{d t} = \frac{df}{d t}

= t \frac{df}{d t} + \frac{df}{d t}

(2 x - 3) (2 x^{2} = 3 x - 7)

1 - e^{- x} (1 + x)

\frac{15}{( 2 - x ) ^{2}}

\frac{\partial}{\partial x} ((x - 1)^{2}) + (y - 2)^{2}

\frac{3 + 9 - 4 k ( 3 k - k ^{3} )}{2 ( 3 k - k ^{3} )}

What is expand (t+1)*(df)/(dt) ?
The solution to expand (t+1)*(df)/(dt) is t(df)/(dt)+(df)/(dt)