What is expand (2sqrt(1-3x))(x+Δx) ?

The solution to expand (2sqrt(1-3x))(x+Δx) is 2xsqrt(1-3x)+2Δxsqrt(1-3x)

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expand (2sqrt(1-3x))(x+Δx)

expand

(2 1 - 3 x) (x + Δ x)

2 x 1 - 3 x + 2Δ x 1 - 3 x

Solution steps

(2 1 - 3 x) (x + Δ x)

Apply the distributive law:

a (b + c) = ab + a c

a = (2 1 - 3 x), b = x, c = Δ x

= (2 1 - 3 x) x + (2 1 - 3 x) Δ x

= x (2 1 - 3 x) + Δ x (2 1 - 3 x)

Remove parentheses:

(a) = a

= 2 x 1 - 3 x + 2Δ x 1 - 3 x

e^{λ t} (t u_{1} + u_{2})

\frac{x + 8}{( x + 4 ) ( x + 2 )}

\frac{0.16 ( s + 1 )}{( s ^{2} + s + 9 )}

- \frac{5 ( 2 \cdot ln ( x ) + 1 )}{x ^{3} e ^{2}}

(4 x + y = 1) 7

What is expand (2sqrt(1-3x))(x+Δx) ?
The solution to expand (2sqrt(1-3x))(x+Δx) is 2xsqrt(1-3x)+2Δxsqrt(1-3x)