What is expand-5/((s+3)(s-3)(s-9)) ?

The solution to expand-5/((s+3)(s-3)(s-9)) is -5/(s^3-9s^2-9s+81)

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expand-5/((s+3)(s-3)(s-9))

expand

- \frac{5}{( s + 3 ) ( s - 3 ) ( s - 9 )}

- \frac{5}{s ^{3} - 9 s ^{2} - 9 s + 81}

Solution steps

- \frac{5}{( s + 3 ) ( s - 3 ) ( s - 9 )}

Expand

(s + 3) (s - 3) (s - 9) : s^{3} - 9 s^{2} - 9 s + 81

= - \frac{5}{s ^{3} - 9 s ^{2} - 9 s + 81}

\frac{3 x ^{2} + 5}{( x ^{2} + 4 ) ^{2}}

\frac{m x ^{m + 1} - ( m + 4 ) x ^{m - 1} + 10}{x - 1}

\frac{( 19 u + 4 ) ^{2}}{361}

\frac{2 x}{( 0.02 - x ) ^{2}}

- \frac{π}{30} sin (\frac{π}{90} (x + 20))

What is expand-5/((s+3)(s-3)(s-9)) ?
The solution to expand-5/((s+3)(s-3)(s-9)) is -5/(s^3-9s^2-9s+81)