What is expand cos(5t)h(t-(11pi)/(10)) ?

The solution to expand cos(5t)h(t-(11pi)/(10)) is thcos(5t)-(11pihcos(5t))/(10)

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expand cos(5t)h(t-(11pi)/(10))

expand

cos (5 t) h (t - \frac{11 π}{10})

t h cos (5 t) - \frac{11 πh cos ( 5 t )}{10}

Solution steps

cos (5 t) h (t - \frac{11 π}{10})

= h cos (5 t) (t - \frac{11 π}{10})

Apply the distributive law:

a (b - c) = ab - a c

a = cos (5 t) h, b = t, c = \frac{11 π}{10}

= cos (5 t) h t - cos (5 t) h \frac{11 π}{10}

= t h cos (5 t) - \frac{11 π}{10} h cos (5 t)

Simplify

t h cos (5 t) - \frac{11 π}{10} h cos (5 t) : t h cos (5 t) - \frac{11 πh cos ( 5 t )}{10}

= t h cos (5 t) - \frac{11 πh cos ( 5 t )}{10}

(1 - \frac{1}{e}) \cdot 2

\frac{( a x + b ) ( ln ( a x + b ) - 1 )}{a}

\frac{2 x ^{2} + 34 x - 300}{x ( x - 5 ) ^{2}}

\frac{k \cdot A}{( t \cdot s + 1 ) s}

\frac{197 π ( e ^{9} - 1 )}{e ^{9}}

What is expand cos(5t)h(t-(11pi)/(10)) ?
The solution to expand cos(5t)h(t-(11pi)/(10)) is thcos(5t)-(11pihcos(5t))/(10)