What is expand i((2+i)x-iy=2) ?

The solution to expand i((2+i)x-iy=2) is (-x+y)+2ix=2

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expand i((2+i)x-iy=2)

expand

i ((2 + i) x - i y = 2)

(- x + y) + 2 i x = 2

Solution steps

i ((2 + i) x - i y = 2)

= i ((2 + i) x - 2 i = y)

Apply the distributive law:

a (b - c) = ab - a c

a = i, b = (2 + i) x, c = i y = 2

i (2 + i) x - ii y = 2

Expand

i (2 + i) x - ii y : (- x + y) + 2 i x

(- x + y) + 2 i x = 2

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What is expand i((2+i)x-iy=2) ?
The solution to expand i((2+i)x-iy=2) is (-x+y)+2ix=2