What is expand (u(t-1))/(e^{ta)} ?

The solution to expand (u(t-1))/(e^{ta)} is (ut)/(e^{ta)}-u/(e^{ta)}

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expand (u(t-1))/(e^{ta)}

expand

\frac{u ( t - 1 )}{e ^{t a}}

\frac{u t}{e ^{t a}} - \frac{u}{e ^{t a}}

Solution steps

\frac{u ( t - 1 )}{e ^{t a}}

Expand

u (t - 1) : u t - u

= \frac{u t - u}{e ^{t a}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{u t - u}{e ^{t a}} = \frac{u t}{e ^{t a}} - \frac{u}{e ^{t a}}

= \frac{u t}{e ^{t a}} - \frac{u}{e ^{t a}}

Δ^{3} y

\frac{a ^{2} ( b - a ) ^{2} ( n + 1 ) ( 2 n + 1 )}{n ^{2}}

\frac{( x + 5 ) ^{2}}{( 30 )}

(\frac{7 + 4 x + 25}{2})^{2}

\frac{\partial}{\partial x} ((u) (a u + b v))

What is expand (u(t-1))/(e^{ta)} ?
The solution to expand (u(t-1))/(e^{ta)} is (ut)/(e^{ta)}-u/(e^{ta)}