What is expand 1/(sin(θ)(1+2cos(θ))) ?

The solution to expand 1/(sin(θ)(1+2cos(θ))) is 1/(sin(θ)+sin(2θ))

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expand 1/(sin(θ)(1+2cos(θ)))

expand

\frac{1}{sin ( θ ) ( 1 + 2 cos ( θ ) )}

\frac{1}{sin ( θ ) + sin ( 2 θ )}

Solution steps

\frac{1}{sin ( θ ) ( 1 + 2 cos ( θ ) )}

Expand

sin (θ) (1 + 2 cos (θ)) : sin (θ) + 2 sin (θ) cos (θ)

= \frac{1}{sin ( θ ) + 2 sin ( θ ) cos ( θ )}

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= \frac{1}{sin ( θ ) + sin ( 2 θ )}

(e^{2} - 2 ey + y^{2}) (e^{2} - 2 x + x^{2}) - (e^{2} - 2 x + x^{2}) r

\frac{4 n ^{3} + 15 n ^{2} + 11 n}{6}

(1 - x) y^{''} (x) + x y

\frac{x ^{2} + y ^{2} + z ^{2}}{2} - \frac{( x + y + z ) ^{2}}{6}

\frac{sec ^{2} ( x )}{( 1 + tan ( x ) ) ^{3}}

What is expand 1/(sin(θ)(1+2cos(θ))) ?
The solution to expand 1/(sin(θ)(1+2cos(θ))) is 1/(sin(θ)+sin(2θ))