What is expand ((x+3)(x+2))/(x-3) ?

The solution to expand ((x+3)(x+2))/(x-3) is (x^2+5x+6)/(x-3)

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expand ((x+3)(x+2))/(x-3)

expand

\frac{( x + 3 ) ( x + 2 )}{x - 3}

\frac{x ^{2} + 5 x + 6}{x - 3}

Solution steps

\frac{( x + 3 ) ( x + 2 )}{x - 3}

Expand

(x + 3) (x + 2) : x^{2} + 5 x + 6

= \frac{x ^{2} + 5 x + 6}{x - 3}

\frac{( x ^{3} )}{( x - 1 ) ( x ^{2} + x + 1 )}

(3 x - 2 y = 2, 2) 3 y (x = 3 y + 19)

\frac{1}{s ( - s b + k )}

30 sin (15 (x - 4)) + 25

\frac{x d v ( 4 + v ^{2} )}{( 4 - v ^{2} ) ( 1 + x ^{2} )}

What is expand ((x+3)(x+2))/(x-3) ?
The solution to expand ((x+3)(x+2))/(x-3) is (x^2+5x+6)/(x-3)