What is expand (3x(4xy+4y^2+x^2))/2 ?

The solution to expand (3x(4xy+4y^2+x^2))/2 is 6x^2y+6xy^2+(3x^3)/2

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expand (3x(4xy+4y^2+x^2))/2

expand

\frac{3 x ( 4 x y + 4 y ^{2} + x ^{2} )}{2}

6 x^{2} y + 6 x y^{2} + \frac{3 x ^{3}}{2}

Solution steps

\frac{3 x ( 4 x y + 4 y ^{2} + x ^{2} )}{2}

Expand

3 x (4 x y + 4 y^{2} + x^{2}) : 12 x^{2} y + 12 x y^{2} + 3 x^{3}

= \frac{12 x ^{2} y + 12 x y ^{2} + 3 x ^{3}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 x ^{2} y + 12 x y ^{2} + 3 x ^{3}}{2} = \frac{12 x ^{2} y}{2} + \frac{12 x y ^{2}}{2} + \frac{3 x ^{3}}{2}

= \frac{12 x ^{2} y}{2} + \frac{12 x y ^{2}}{2} + \frac{3 x ^{3}}{2}

Divide the numbers:

\frac{12}{2} = 6

= 6 x^{2} y + 6 x y^{2} + \frac{3 x ^{3}}{2}

, - 0.0625 + (0.4 - x)^{2} (1 + 0.1 (5 - x))

735 (z - 1) (z - e^{- T}) (z - e^{- 7 T})

(\frac{1}{2}) (x^{2} + \cdot + 1)^{\frac{- 1}{2}} (2 x + 1)

5 (e^{7 x - 7 y} + 7 e^{7 x - 7 y} x)

\frac{1}{2} e^{(x^{2} - 1) (3 x)}

What is expand (3x(4xy+4y^2+x^2))/2 ?
The solution to expand (3x(4xy+4y^2+x^2))/2 is 6x^2y+6xy^2+(3x^3)/2