What are the solutions to the equation x^2+2=6x ?

The solutions to the equation x^2+2=6x are x=3+sqrt(7),x=3-sqrt(7)

Find the zeros of x^2+2=6x

The zeros of x^2+2=6x are x=3+sqrt(7),x=3-sqrt(7)

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x^{2} + 2 = 6 x

x = 3 + 7, x = 3 - 7

Decimal Notation

x = 5.64575 \dots, x = 0.35424 \dots

Solution steps

x^{2} + 2 = 6 x

Move

6 x

to the left side

x^{2} + 2 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 2 = 27

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 7}{2 \cdot 1} : 3 + 7

x = \frac{- ( - 6 ) - 2 7}{2 \cdot 1} : 3 - 7

The solutions to the quadratic equation are:

x = 3 + 7, x = 3 - 7

\frac{\frac{15 n - 20}{5}}{\frac{9 n ^{3} - 12 n ^{2}}{7 n}}

a^{2} - b^{2}

17 \geq h - 2 > - 15

(x - 5)^{2} (32 - 4 x) > 0

\leq 0 = 2 x + 11

What are the solutions to the equation x^2+2=6x ?
The solutions to the equation x^2+2=6x are x=3+sqrt(7),x=3-sqrt(7)
Find the zeros of x^2+2=6x
The zeros of x^2+2=6x are x=3+sqrt(7),x=3-sqrt(7)