What is expand (x^2-2x-1)^5 ?

The solution to expand (x^2-2x-1)^5 is x^{10}-10x^9+35x^8-40x^7-30x^6+68x^5+30x^4-40x^3-35x^2-10x-1

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expand (x^2-2x-1)^5

expand

(x^{2} - 2 x - 1)^{5}

x^{10} - 10 x^{9} + 35 x^{8} - 40 x^{7} - 30 x^{6} + 68 x^{5} + 30 x^{4} - 40 x^{3} - 35 x^{2} - 10 x - 1

Solution steps

(x^{2} - 2 x - 1)^{5}

(x^{2} - 2 x - 1)^{5} = (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1)

= (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1)

Expand

(x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) (x^{2} - 2 x - 1) : x^{10} - 10 x^{9} + 35 x^{8} - 40 x^{7} - 30 x^{6} + 68 x^{5} + 30 x^{4} - 40 x^{3} - 35 x^{2} - 10 x - 1

= x^{10} - 10 x^{9} + 35 x^{8} - 40 x^{7} - 30 x^{6} + 68 x^{5} + 30 x^{4} - 40 x^{3} - 35 x^{2} - 10 x - 1

\frac{( L + d - x )}{( ( L + d - x ) ^{2} + h ^{2} ) ^{\frac{3}{2}}}

\frac{d ^{2}}{d x ^{2}} ((y) (4 (2 x + 2) sin (x^{2} + 2 x + \frac{π}{2})))

3 + 0 (x - 1)

\frac{- 2 ( 0 ) + 9}{- ( 0 ) ^{2} + 9}

dd x (e^{x^{4}} + ln (5) (π))

What is expand (x^2-2x-1)^5 ?
The solution to expand (x^2-2x-1)^5 is x^{10}-10x^9+35x^8-40x^7-30x^6+68x^5+30x^4-40x^3-35x^2-10x-1