What are the solutions to the equation -4x^2-20x+10=0 ?

The solutions to the equation -4x^2-20x+10=0 are x=-(5+sqrt(35))/2 ,x=(sqrt(35)-5)/2

Find the zeros of -4x^2-20x+10=0

The zeros of -4x^2-20x+10=0 are x=-(5+sqrt(35))/2 ,x=(sqrt(35)-5)/2

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- 4 x^{2} - 20 x + 10 = 0

x = - \frac{5 + 35}{2}, x = \frac{35 - 5}{2}

Decimal Notation

x = - 5.45803 \dots, x = 0.45803 \dots

Solution steps

- 4 x^{2} - 20 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 4 ) \cdot 10}{2 ( - 4 )}

(- 20)^{2} - 4 (- 4) \cdot 10 = 435

x_{1, 2} = \frac{- ( - 20 ) \pm 4 35}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 35}{2 ( - 4 )}, x_{2} = \frac{- ( - 20 ) - 4 35}{2 ( - 4 )}

x = \frac{- ( - 20 ) + 4 35}{2 ( - 4 )} : - \frac{5 + 35}{2}

x = \frac{- ( - 20 ) - 4 35}{2 ( - 4 )} : \frac{35 - 5}{2}

The solutions to the quadratic equation are:

x = - \frac{5 + 35}{2}, x = \frac{35 - 5}{2}

r^{2} - 4 r + 2 = 0

2 (x + 7) = 6 x + 9 - 4 x

3 x^{2} + 3 x - 6

\frac{1}{2} \cdot 9.8

z^{2} + 6 z - 27

What are the solutions to the equation -4x^2-20x+10=0 ?
The solutions to the equation -4x^2-20x+10=0 are x=-(5+sqrt(35))/2 ,x=(sqrt(35)-5)/2
Find the zeros of -4x^2-20x+10=0
The zeros of -4x^2-20x+10=0 are x=-(5+sqrt(35))/2 ,x=(sqrt(35)-5)/2