What is expand ln(1-x)(1+x)-ln(1+x)(1+x) ?

The solution to expand ln(1-x)(1+x)-ln(1+x)(1+x) is ln(1-x)+xln(1-x)-ln(1+x)-xln(1+x)

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expand ln(1-x)(1+x)-ln(1+x)(1+x)

expand

ln (1 - x) (1 + x) - ln (1 + x) (1 + x)

ln (1 - x) + x ln (1 - x) - ln (1 + x) - x ln (1 + x)

Solution steps

ln (1 - x) (1 + x) - ln (1 + x) (1 + x)

Expand

ln (1 - x) (1 + x) : ln (1 - x) + x ln (1 - x)

= ln (1 - x) + x ln (1 - x) - ln (1 + x) (1 + x)

Expand

- ln (1 + x) (1 + x) : - ln (1 + x) - x ln (1 + x)

= ln (1 - x) + x ln (1 - x) - ln (1 + x) - x ln (1 + x)

f (z) (\frac{ln ( 4 x y )}{z ^{2}} + sin (x y^{2} + y e^{z}))

\frac{36 x y 2 ^{2}}{12 x y ^{2}}

\frac{6 x - 3}{( x + 1 ) ( 4 x - 5 )}

\frac{3 x ^{2} - 5 x - 5}{x ( x + 1 )}

(e^{z s i n (x)} (z) + 5 sin (z))^{4}

What is expand ln(1-x)(1+x)-ln(1+x)(1+x) ?
The solution to expand ln(1-x)(1+x)-ln(1+x)(1+x) is ln(1-x)+xln(1-x)-ln(1+x)-xln(1+x)