What is expand 2t+(e^{-3t}-2t)θ(t-5) ?

The solution to expand 2t+(e^{-3t}-2t)θ(t-5) is 2t+e^{-3t}tθ-5e^{-3t}θ-2t^2θ+10tθ

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expand 2t+(e^{-3t}-2t)θ(t-5)

expand

2 t + (e^{- 3 t} - 2 t) θ (t - 5)

2 t + e^{- 3 t} tθ - 5 e^{- 3 t} θ - 2 t^{2} θ + 10 tθ

Solution steps

2 t + (e^{- 3 t} - 2 t) θ (t - 5)

= 2 t + θ (e^{- 3 t} - 2 t) (t - 5)

Expand

(e^{- 3 t} - 2 t) θ (t - 5) : e^{- 3 t} tθ - 5 e^{- 3 t} θ - 2 t^{2} θ + 10 tθ

= 2 t + e^{- 3 t} tθ - 5 e^{- 3 t} θ - 2 t^{2} θ + 10 tθ

e^{3 x} (2 x + y^{2} + 3 y)

\frac{ln ( 4 n )}{ln ( 4 ( n + 1 ) )}

\frac{x ^{4} - 5 x ^{3} + 6 x ^{2} + 4 x - 8}{x + 1}

\frac{11 ( x ^{2} + 2 3 x y + 3 y ^{2} )}{4}

\frac{s + 3}{( s + 1 ) ( s ^{2} + 2 s + 3 )}

What is expand 2t+(e^{-3t}-2t)θ(t-5) ?
The solution to expand 2t+(e^{-3t}-2t)θ(t-5) is 2t+e^{-3t}tθ-5e^{-3t}θ-2t^2θ+10tθ