What are the solutions to the equation (2x+7)(3x-1)=0 ?

The solutions to the equation (2x+7)(3x-1)=0 are x=-7/2 ,x= 1/3

Find the zeros of (2x+7)(3x-1)=0

The zeros of (2x+7)(3x-1)=0 are x=-7/2 ,x= 1/3

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(2 x + 7) (3 x - 1) = 0

x = - \frac{7}{2}, x = \frac{1}{3}

Decimal Notation

x = - 3.5, x = 0.33333 \dots

Solution steps

(2 x + 7) (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 7 = 0 or 3 x - 1 = 0

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions to the quadratic equation are:

x = - \frac{7}{2}, x = \frac{1}{3}

\frac{5}{7} x = 35

(2.5 a^{8 n})^{3} \cdot (0. 4^{7 n})^{3}

12 x^{2} - 36 x + 15 = 0

7 x^{2} - 10 = - 33 x

2 + \frac{1}{2}

What are the solutions to the equation (2x+7)(3x-1)=0 ?
The solutions to the equation (2x+7)(3x-1)=0 are x=-7/2 ,x= 1/3
Find the zeros of (2x+7)(3x-1)=0
The zeros of (2x+7)(3x-1)=0 are x=-7/2 ,x= 1/3