What is expand (pi+3(sqrt(3)-2))/(24) ?

The solution to expand (pi+3(sqrt(3)-2))/(24) is pi/(24)+(sqrt(3))/8-1/4

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expand (pi+3(sqrt(3)-2))/(24)

expand

\frac{π + 3 ( 3 - 2 )}{24}

\frac{π}{24} + \frac{3}{8} - \frac{1}{4}

Decimal Notation

0.09740 \dots

Solution steps

\frac{π + 3 ( 3 - 2 )}{24}

Expand

π + 3 (3 - 2) : π + 33 - 6

= \frac{π + 3 3 - 6}{24}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π + 3 3 - 6}{24} = \frac{π}{24} + \frac{3 3}{24} - \frac{6}{24}

= \frac{π}{24} + \frac{3 3}{24} - \frac{6}{24}

Cancel

\frac{3 3}{24} : \frac{3}{8}

= \frac{π}{24} + \frac{3}{8} - \frac{6}{24}

Cancel

\frac{6}{24} : \frac{1}{4}

= \frac{π}{24} + \frac{3}{8} - \frac{1}{4}

\frac{22 ( 10 h + 2 j - 11 k )}{45}

(x - 2)^{8}

65 \cdot 13

\frac{( x - 1 ) ^{2}}{( x + 2 ) ( x + 3 ) ( ( x ^{2} + 4 x + 13 ) )}

(cos (53.1 3^{\circ}) + sin (53.1 3^{\circ}) x) 10

What is expand (pi+3(sqrt(3)-2))/(24) ?
The solution to expand (pi+3(sqrt(3)-2))/(24) is pi/(24)+(sqrt(3))/8-1/4