What is expand 1/((m+3)(m+2)(4m+12)) ?

The solution to expand 1/((m+3)(m+2)(4m+12)) is 1/(4m^3+32m^2+84m+72)

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expand 1/((m+3)(m+2)(4m+12))

expand

\frac{1}{( m + 3 ) ( m + 2 ) ( 4 m + 12 )}

\frac{1}{4 m ^{3} + 32 m ^{2} + 84 m + 72}

Solution steps

\frac{1}{( m + 3 ) ( m + 2 ) ( 4 m + 12 )}

Expand

(m + 3) (m + 2) (4 m + 12) : 4 m^{3} + 32 m^{2} + 84 m + 72

= \frac{1}{4 m ^{3} + 32 m ^{2} + 84 m + 72}

- \frac{2 ( - x + 1 ) ^{3}}{3}

\frac{( 3 sin ( θ ) + 3 ) ^{2}}{2}

\frac{1}{2 u ^{3}} (u \cdot \frac{1}{2} x - v + u^{3} = 0)

(sinh (x)) (coth^{2} (x) + csch^{3} (x)) d x

\frac{3 x ^{2} - 2 x}{( 2 x - 1 ) ^{\frac{3}{2}}}

What is expand 1/((m+3)(m+2)(4m+12)) ?
The solution to expand 1/((m+3)(m+2)(4m+12)) is 1/(4m^3+32m^2+84m+72)