en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+8x>= 5

Solution

4 x^{2} + 8 x \geq 5

Solution

x \leq - \frac{5}{2} or x \geq \frac{1}{2}

+2

Interval Notation

(- \infty, - \frac{5}{2}] \cup [\frac{1}{2}, \infty)

Decimal Notation

x \leq - 2.5 or x \geq 0.5

Solution steps

4 x^{2} + 8 x \geq 5

Rewrite in standard form

4 x^{2} + 8 x - 5 \geq 0

Factor

4 x^{2} + 8 x - 5 : (2 x - 1) (2 x + 5)

(2 x - 1) (2 x + 5) \geq 0

Identify the intervals

x \leq - \frac{5}{2} or x \geq \frac{1}{2}

Popular Examples

2/(3x-1)>(-5)/x

\frac{2}{3 x - 1} > \frac{- 5}{x}

(x-12)/6 >= (x-6)/9+5/18

\frac{x - 12}{6} \geq \frac{x - 6}{9} + \frac{5}{18}

∣ 3 x - 11 ∣ \leq 19

factor 4j-10k factor

4 j - 10 k

factor 2x^2+5x-12 factor

2 x^{2} + 5 x - 12

Frequently Asked Questions (FAQ)

What is 4x^2+8x>= 5 ?
The solution to 4x^2+8x>= 5 is x<=-5/2 \lor x>= 1/2