What is expand f(|x|-1)e^{|x|} ?

The solution to expand f(|x|-1)e^{|x|} is e^{|x|}f|x|-e^{|x|}f

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expand f(|x|-1)e^{|x|}

expand

f (∣ x ∣ - 1) e^{∣ x ∣}

e^{∣ x ∣} f ∣ x ∣ - e^{∣ x ∣} f

Solution steps

f (∣ x ∣ - 1) e^{∣ x ∣}

= e^{∣ x ∣} f (∣ x ∣ - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = f e^{∣ x ∣}, b = ∣ x ∣, c = 1

= f e^{∣ x ∣} ∣ x ∣ - f e^{∣ x ∣} \cdot 1

= e^{∣ x ∣} f ∣ x ∣ - 1 \cdot e^{∣ x ∣} f

Multiply:

1 \cdot e^{∣ x ∣} = e^{∣ x ∣}

= e^{∣ x ∣} f ∣ x ∣ - e^{∣ x ∣} f

1 - x ((- 2 - x) (4 - x))

\frac{[ x ( x - 1 ) - 2 ]}{2}

2 x 2 x^{1}

\frac{1}{1172 - 5} (121 - 1) 15.8 1^{2} De t er min e

\frac{3 s + 2}{( s ^{2} + 2 ) ( s - 4 )}

What is expand f(|x|-1)e^{|x|} ?
The solution to expand f(|x|-1)e^{|x|} is e^{|x|}f|x|-e^{|x|}f