What is expand 1/(3a^2b^2(b+a)) ?

The solution to expand 1/(3a^2b^2(b+a)) is 1/(3a^2b^3+3a^3b^2)

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expand 1/(3a^2b^2(b+a))

expand

\frac{1}{3 a ^{2} b ^{2} ( b + a )}

\frac{1}{3 a ^{2} b ^{3} + 3 a ^{3} b ^{2}}

Solution steps

\frac{1}{3 a ^{2} b ^{2} ( b + a )}

Expand

3 a^{2} b^{2} (b + a) : 3 a^{2} b^{3} + 3 a^{3} b^{2}

= \frac{1}{3 a ^{2} b ^{3} + 3 a ^{3} b ^{2}}

\frac{x ^{2} + 3 x}{( 3 x + 1 ) ^{2}}

((e^{1.1 x} - e^{- 1.1 x}))^{2}

e^{(4 x)} (4 x - 16)

\frac{( 3 ^{(n + 1) (n + 2)} + 65 )}{72}

e^{x} (x^{2} - 2 x - 7)

What is expand 1/(3a^2b^2(b+a)) ?
The solution to expand 1/(3a^2b^2(b+a)) is 1/(3a^2b^3+3a^3b^2)