What is expand 4/(s(x^2-4x+5)(x^2-1)) ?

The solution to expand 4/(s(x^2-4x+5)(x^2-1)) is 4/(sx^4+4sx^2-4sx^3+4sx-5s)

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expand 4/(s(x^2-4x+5)(x^2-1))

expand

\frac{4}{s ( x ^{2} - 4 x + 5 ) ( x ^{2} - 1 )}

\frac{4}{s x ^{4} + 4 s x ^{2} - 4 s x ^{3} + 4 s x - 5 s}

Solution steps

\frac{4}{s ( x ^{2} - 4 x + 5 ) ( x ^{2} - 1 )}

Expand

s (x^{2} - 4 x + 5) (x^{2} - 1) : s x^{4} + 4 s x^{2} - 4 s x^{3} + 4 s x - 5 s

= \frac{4}{s x ^{4} + 4 s x ^{2} - 4 s x ^{3} + 4 s x - 5 s}

(x y^{2} + b x^{2} y) d x + (x + y) x^{2} d y

\frac{10}{s ( s + 5 ) ( s + 2 )}

\frac{x ( - x + 8 ) ^{4}}{2}

\frac{6.106 N \cdot 20 m}{0.31 m ^{2} \cdot 2 \cdot 1 0 ^{11}}

(6 y - 12 x^{2} z) a t (2, - 1, 0)

What is expand 4/(s(x^2-4x+5)(x^2-1)) ?
The solution to expand 4/(s(x^2-4x+5)(x^2-1)) is 4/(sx^4+4sx^2-4sx^3+4sx-5s)