What is expand tan(4x)(1+sin(x)-1=0) ?

The solution to expand tan(4x)(1+sin(x)-1=0) is tan(4x)sin(x)=0

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expand tan(4x)(1+sin(x)-1=0)

expand

tan (4 x) (1 + sin (x) - 1 = 0)

tan (4 x) sin (x) = 0

Solution steps

tan (4 x) (1 + sin (x) - 1 = 0)

= tan (4 x) (1 + sin (x) - 1 \cdot 0 =)

Distribute parentheses

= tan (4 x) \cdot 1 + tan (4 x) sin (x) + tan (4 x) (- 1 = 0)

Apply minus-plus rules

+ (- a) = - a

1 \cdot tan (4 x) + tan (4 x) sin (x) - 1 \cdot tan (4 x) = 0

Expand

1 \cdot tan (4 x) + tan (4 x) sin (x) - 1 \cdot tan (4 x) : tan (4 x) sin (x)

tan (4 x) sin (x) = 0

e^{- 3 x} (\frac{e ^{3 x} x}{3} - e^{3 x}) + \frac{1}{5} e^{5 x}

\frac{( s + 1500 )}{s ( s + 200 )}

\frac{d ^{2}}{d x ^{2}} ((f (x)) (4 x^{2} - 5 x - 2))

y^{3} (10 - 6 y + e^{- 3 x})

[cos (2 t) \cdot u (t - 2 π)] [3 (1 - u (t - 2 π))]

What is expand tan(4x)(1+sin(x)-1=0) ?
The solution to expand tan(4x)(1+sin(x)-1=0) is tan(4x)sin(x)=0