What is expand-(b(4a^4b-3))/(2c(3abc+2)) ?

The solution to expand-(b(4a^4b-3))/(2c(3abc+2)) is -(4b^2a^4-3b)/(6bac^2+4c)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(b(4a^4b-3))/(2c(3abc+2))

expand

- \frac{b ( 4 a ^{4} b - 3 )}{2 c ( 3 ab c + 2 )}

- \frac{4 b ^{2} a ^{4} - 3 b}{6 ba c ^{2} + 4 c}

Solution steps

- \frac{b ( 4 a ^{4} b - 3 )}{2 c ( 3 ab c + 2 )}

Expand

2 c (3 ab c + 2) : 6 ba c^{2} + 4 c

= - \frac{b ( 4 b a ^{4} - 3 )}{6 ba c ^{2} + 4 c}

Expand

b (4 a^{4} b - 3) : 4 b^{2} a^{4} - 3 b

= - \frac{4 b ^{2} a ^{4} - 3 b}{6 ba c ^{2} + 4 c}

\frac{4 x}{( x ^{2} + 1 ) ( x ^{2} - 1 )}

csc (θ) (25, - 4)

(x + 2^{^{'}})^{5}

e^{\frac{( x ^{y} e ^{- y} )}{y ! ( 1 - e ^{- x} )}}

\frac{( 3 x + 25 ) ^{2}}{16}

What is expand-(b(4a^4b-3))/(2c(3abc+2)) ?
The solution to expand-(b(4a^4b-3))/(2c(3abc+2)) is -(4b^2a^4-3b)/(6bac^2+4c)