What is expand ((a-bc)^2)/(4n^2) ?

The solution to expand ((a-bc)^2)/(4n^2) is (a^2)/(4n^2)-(abc)/(2n^2)+(b^2c^2)/(4n^2)

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expand ((a-bc)^2)/(4n^2)

expand

\frac{( a - b c ) ^{2}}{4 n ^{2}}

\frac{a ^{2}}{4 n ^{2}} - \frac{ab c}{2 n ^{2}} + \frac{b ^{2} c ^{2}}{4 n ^{2}}

Solution steps

\frac{( a - b c ) ^{2}}{4 n ^{2}}

(a - b c)^{2} = a^{2} - 2 ab c + b^{2} c^{2}

= \frac{a ^{2} - 2 ab c + b ^{2} c ^{2}}{4 n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{a ^{2} - 2 ab c + b ^{2} c ^{2}}{4 n ^{2}} = \frac{a ^{2}}{4 n ^{2}} - \frac{2 ab c}{4 n ^{2}} + \frac{b ^{2} c ^{2}}{4 n ^{2}}

= \frac{a ^{2}}{4 n ^{2}} - \frac{2 ab c}{4 n ^{2}} + \frac{b ^{2} c ^{2}}{4 n ^{2}}

Cancel

\frac{2 ab c}{4 n ^{2}} : \frac{ab c}{2 n ^{2}}

= \frac{a ^{2}}{4 n ^{2}} - \frac{ab c}{2 n ^{2}} + \frac{b ^{2} c ^{2}}{4 n ^{2}}

(2 + 5 = 6,) v (5 - 3 = 4)

\frac{t ( x _{2} - x _{1} ) ( 2 + x _{1} + x _{2} )}{3}

\frac{3 ( 15 x - 3 )}{( x + 2 )}

\frac{12 e ^{- 2 s} + 12 e ^{- 5 s} + 3 s}{s ( 3 + s )}

(2 x + e^{x}) (x^{2} - e^{x})

What is expand ((a-bc)^2)/(4n^2) ?
The solution to expand ((a-bc)^2)/(4n^2) is (a^2)/(4n^2)-(abc)/(2n^2)+(b^2c^2)/(4n^2)