What is expand ((2x-1)/(x+1))^2 ?

The solution to expand ((2x-1)/(x+1))^2 is (4x^2-4x+1)/(x^2+2x+1)

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expand ((2x-1)/(x+1))^2

expand

(\frac{2 x - 1}{x + 1})^{2}

\frac{4 x ^{2} - 4 x + 1}{x ^{2} + 2 x + 1}

Solution steps

(\frac{2 x - 1}{x + 1})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x - 1 ) ^{2}}{( x + 1 ) ^{2}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{( 2 x - 1 ) ^{2}}{x ^{2} + 2 x + 1}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{4 x ^{2} - 4 x + 1}{x ^{2} + 2 x + 1}

\frac{2 ( x + 6 )}{( x + 4 ) ( x - 4 )}

x (x^{2} + 3 x + 2)^{2}

\frac{( x + 2 ) ( x + 1 )}{2}

π (2 + ln (2 - 1))

\frac{s ^{3} + 25 s + 2 s ^{2} + 55}{( s ^{2} + 2 s + 2 ) ( s ^{2} + 25 )}

What is expand ((2x-1)/(x+1))^2 ?
The solution to expand ((2x-1)/(x+1))^2 is (4x^2-4x+1)/(x^2+2x+1)