What is expand 10(125/2 e^{-x}-125/2 e^{-5x}) ?

The solution to expand 10(125/2 e^{-x}-125/2 e^{-5x}) is 625e^{-x}-625e^{-5x}

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expand 10(125/2 e^{-x}-125/2 e^{-5x})

expand

10 (\frac{125}{2} e^{- x} - \frac{125}{2} e^{- 5 x})

625 e^{- x} - 625 e^{- 5 x}

Solution steps

10 (\frac{125}{2} e^{- x} - \frac{125}{2} e^{- 5 x})

Apply the distributive law:

a (b - c) = ab - a c

a = 10, b = \frac{125}{2} e^{- x}, c = \frac{125}{2} e^{- 5 x}

= 10 \cdot \frac{125}{2} e^{- x} - 10 \cdot \frac{125}{2} e^{- 5 x}

Simplify

10 \cdot \frac{125}{2} e^{- x} - 10 \cdot \frac{125}{2} e^{- 5 x} : 625 e^{- x} - 625 e^{- 5 x}

= 625 e^{- x} - 625 e^{- 5 x}

- \frac{2}{5} (26.74 + z) - \frac{2}{5} (26, 26 + z) + \frac{2}{25}

(11 k^{7} m^{4} + 76 d^{4} e^{7}) (11 k^{7} m^{4} - 76 d^{4} e^{7})

tan (0)

\frac{2 h ^{3} - 5 h ^{2} + h}{h ^{4} - h ^{2}}

(3 d - 5 e) (9 d^{2} - 15 d e + 25 e^{2})

What is expand 10(125/2 e^{-x}-125/2 e^{-5x}) ?
The solution to expand 10(125/2 e^{-x}-125/2 e^{-5x}) is 625e^{-x}-625e^{-5x}