What is expand sin(t)(h)(t-2pi) ?

The solution to expand sin(t)(h)(t-2pi) is thsin(t)-2pihsin(t)

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expand sin(t)(h)(t-2pi)

expand

sin (t) (h) (t - 2 π)

t h sin (t) - 2 πh sin (t)

Solution steps

sin (t) (h) (t - 2 π)

= (h) sin (t) (t - 2 π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (t) (h), b = t, c = 2 π

= sin (t) (h) t - sin (t) (h) \cdot 2 π

= t (h) sin (t) - 2 π (h) sin (t)

Remove parentheses:

(a) = a

= t h sin (t) - 2 πh sin (t)

D x (\frac{cos ( x )}{ln ( x )} - 1)

(x - 1)^{2} \cdot e^{x - 4}

2 x \cdot x^{3}

\frac{( x - 4 ) ( x - 5 )}{( x - 3 ) ^{2} ( x ^{2} + 2 x + 1 )}

\frac{d}{d z} ((z) (x y^{7} - x^{2} y))

What is expand sin(t)(h)(t-2pi) ?
The solution to expand sin(t)(h)(t-2pi) is thsin(t)-2pihsin(t)