What is expand (6x+7)/((15x+5)(x-9)') ?

The solution to expand (6x+7)/((15x+5)(x-9)') is (6x+7)/(15x(x-9)'+5(x-9)')

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expand (6x+7)/((15x+5)(x-9)')

expand

\frac{6 x + 7}{( 15 x + 5 ) ( x - 9 ) ^{'}}

\frac{6 x + 7}{15 x ( x - 9 ) ' + 5 ( x - 9 ) '}

Solution steps

\frac{6 x + 7}{( 15 x + 5 ) ( x - 9 ) ^{'}}

Expand

(15 x + 5) (x - 9)^{'} : 15 x (x - 9)^{'} + 5 (x - 9)^{'}

= \frac{6 x + 7}{15 x ( x - 9 ) ^{'} + 5 ( x - 9 ) ^{'}}

\frac{\partial}{\partial x} ((z) ((x + 2 y)^{2}))

\frac{( 8 k + 2 ) ( 8 k + 7 )}{3}

ln (x + 3) \cdot (- 6 x - 18)

\frac{700}{( s + 15 ) ( s ^{2} + 4 s + 100 )}

\frac{2 x ( 90 - 2 x ) + π x ^{2}}{9}

What is expand (6x+7)/((15x+5)(x-9)') ?
The solution to expand (6x+7)/((15x+5)(x-9)') is (6x+7)/(15x(x-9)'+5(x-9)')