What is (3y^3+4yx+1+2x^2+9y^2x) ?

The solution to (3y^3+4yx+1+2x^2+9y^2x) is 3y^3+4yx+1+2x^2+9y^2x

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(3y^3+4yx+1+2x^2+9y^2x)

simplify

3 y^{3} + 4 y x + 1 + 2 x^{2} + 9 y^{2} x

3 y^{3} + 4 y x + 1 + 2 x^{2} + 9 y^{2} x

Solution steps

3 y^{3} + 4 y x + 1 + 2 x^{2} + 9 y^{2} x

Could not simplify further

= 3 y^{3} + 4 y x + 1 + 2 x^{2} + 9 y^{2} x

3 x + 5 + 3 x + 5

\frac{d}{d A} ([(A + B) C]^{^{'}} + B^{^{'}})

- \frac{21 x ^{2} + 2}{( 7 x ^{3} + 2 x - 4 ) ^{2}}

e^{4 x^{2} + 4 x + 3} (8 x + 4) \cdot cos (e^{4 x^{2} + 4 x + 3})

\frac{2 ( x + y )}{1 + 2 x}

What is (3y^3+4yx+1+2x^2+9y^2x) ?
The solution to (3y^3+4yx+1+2x^2+9y^2x) is 3y^3+4yx+1+2x^2+9y^2x