What is the d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) ?

The d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) is s(-3/pi sin(4t)+3/pi cos(7t))

What is the first d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) ?

The first d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) is s(-3/pi sin(4t)+3/pi cos(7t))

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\frac{d}{d t} ((s) (\frac{3}{4 π} cos (4 t) + \frac{3}{7 π} sin (7 t)))

s (- \frac{3}{π} sin (4 t) + \frac{3}{π} cos (7 t))

Solution steps

\frac{d}{d t} ((s) (\frac{3}{4 π} cos (4 t) + \frac{3}{7 π} sin (7 t)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \frac{d}{d t} (\frac{3}{4 π} cos (4 t) + \frac{3}{7 π} sin (7 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= s (\frac{d}{d t} (\frac{3}{4 π} cos (4 t)) + \frac{d}{d t} (\frac{3}{7 π} sin (7 t)))

\frac{d}{d t} (\frac{3}{4 π} cos (4 t)) = - \frac{3}{π} sin (4 t)

\frac{d}{d t} (\frac{3}{7 π} sin (7 t)) = \frac{3}{π} cos (7 t)

= s (- \frac{3}{π} sin (4 t) + \frac{3}{π} cos (7 t))

\frac{1}{2 ( x + 7 )}

- 5 (\frac{- 5 - 3 y}{10} - 4 y = 10)

\frac{1}{( s ^{3} ( s ^{2} + w ^{2} ) )}

\frac{0.114 + x}{( 1.448 - 2 x ) ^{2}}

(- 2 i, 3 j, - 1 k) - (3 i - 2 j, - 1 k)

What is the d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) ?
The d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) is s(-3/pi sin(4t)+3/pi cos(7t))
What is the first d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) ?
The first d/(dt)((s)(3/(4pi)cos(4t)+3/(7pi)sin(7t))) is s(-3/pi sin(4t)+3/pi cos(7t))