What is expand 1/6 (e^{3x}+e^{-3x}) ?

The solution to expand 1/6 (e^{3x}+e^{-3x}) is 1/6 e^{3x}+1/6 e^{-3x}

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expand 1/6 (e^{3x}+e^{-3x})

expand

\frac{1}{6} (e^{3 x} + e^{- 3 x})

\frac{1}{6} e^{3 x} + \frac{1}{6} e^{- 3 x}

Solution steps

\frac{1}{6} (e^{3 x} + e^{- 3 x})

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{6}, b = e^{3 x}, c = e^{- 3 x}

= \frac{1}{6} e^{3 x} + \frac{1}{6} e^{- 3 x}

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(3 x + 4 y = 3, 2) (5 x + 6 y = 30)

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What is expand 1/6 (e^{3x}+e^{-3x}) ?
The solution to expand 1/6 (e^{3x}+e^{-3x}) is 1/6 e^{3x}+1/6 e^{-3x}