What is -4<(-5y-17)/3 <= 1 ?

The solution to -4<(-5y-17)/3 <= 1 is -4<= y<-1

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-4<(-5y-17)/3 <= 1

- 4 < \frac{- 5 y - 17}{3} \leq 1

- 4 \leq y < - 1

Interval Notation

[- 4, - 1)

Solution steps

- 4 < \frac{- 5 y - 17}{3} \leq 1

a < u \leq b

then

a < u and u \leq b

- 4 < \frac{- 5 y - 17}{3} and \frac{- 5 y - 17}{3} \leq 1

- 4 < \frac{- 5 y - 17}{3} : y < - 1

\frac{- 5 y - 17}{3} \leq 1 : y \geq - 4

Combine the intervals

y < - 1 and y \geq - 4

Merge Overlapping Intervals

- 4 \leq y < - 1

- 8 - (- 4)

f = (\frac{1}{3})^{- 1}

3 x^{2} = 3 x

\frac{2}{5} x - 2 = \frac{- x}{2} \frac{- 4}{3} x

\frac{5 x ^{3} y + 10 x ^{2} y ^{2}}{15 x}