What is the value of cos(pi/2+pi) ?

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cos(pi/2+pi)

cos (\frac{π}{2} + π)

0

Solution steps

cos (\frac{π}{2} + π)

Rewrite using trig identities:

cos (π) cos (\frac{π}{2}) - sin (π) sin (\frac{π}{2})

= cos (π) cos (\frac{π}{2}) - sin (π) sin (\frac{π}{2})

Use the following trivial identity:

cos (π) = (- 1)

Use the following trivial identity:

cos (\frac{π}{2}) = 0

Use the following trivial identity:

sin (π) = 0

Use the following trivial identity:

sin (\frac{π}{2}) = 1

= (- 1) \cdot 0 - 0 \cdot 1

Simplify

= 0

\frac{x - 11}{( x - 2 ) ( x - 5 )}

x^{'} \cdot (x + 1) + x (x + 1)^{^{'}}

\frac{120 e ^{- 0.5 s}}{s ( s + 2 ) ( s + 5 )}

- \frac{18}{( 2 + x ) ^{4}}

\frac{6 x + 1}{( x + 1 ) ^{3} ( x ^{2} + 7 ) ^{2}}