What is expand 1/((s^2+1)(s-1)) ?

The solution to expand 1/((s^2+1)(s-1)) is 1/(s^3-s^2+s-1)

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expand 1/((s^2+1)(s-1))

expand

\frac{1}{( s ^{2} + 1 ) ( s - 1 )}

\frac{1}{s ^{3} - s ^{2} + s - 1}

Solution steps

\frac{1}{( s ^{2} + 1 ) ( s - 1 )}

Expand

(s^{2} + 1) (s - 1) : s^{3} - s^{2} + s - 1

= \frac{1}{s ^{3} - s ^{2} + s - 1}

\frac{4 ( 6 + 786 )}{25}

sin (\frac{2}{3} (x + 2 π))

\frac{2 ( a ^{2} - b ^{2} )}{ab}

u^{2} + (6) u - (\frac{( - 7 ) ^{3}}{27})

\frac{( a x + x ) ( a y + y )}{a ^{2}}

What is expand 1/((s^2+1)(s-1)) ?
The solution to expand 1/((s^2+1)(s-1)) is 1/(s^3-s^2+s-1)