What is expand x^2(1/x-ln(1+1/x)) ?

The solution to expand x^2(1/x-ln(1+1/x)) is x-x^2ln(1+1/x)

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expand x^2(1/x-ln(1+1/x))

expand

x^{2} (\frac{1}{x} - ln (1 + \frac{1}{x}))

x - x^{2} ln (1 + \frac{1}{x})

Solution steps

x^{2} (\frac{1}{x} - ln (1 + \frac{1}{x}))

Apply the distributive law:

a (b - c) = ab - a c

a = x^{2}, b = \frac{1}{x}, c = ln (1 + \frac{1}{x})

= x^{2} \frac{1}{x} - x^{2} ln (1 + \frac{1}{x})

= \frac{1}{x} x^{2} - x^{2} ln (1 + \frac{1}{x})

\frac{1}{x} x^{2} = x

= x - x^{2} ln (1 + \frac{1}{x})

- 3 - 3 (2 x + 79 + (- 5 x + 6) - 8 (1 - 2 x) - (x - 3) = 0)

\frac{2000}{( x + 100 ) ^{3}}

\frac{d}{d p} ((q) (2 p^{2} + q^{2} - 1000))

\frac{3 ^{2} - 25}{3 - 6}

(338.76 + 84.69 x)^{2} + (- 206 - 64 x)^{s}

What is expand x^2(1/x-ln(1+1/x)) ?
The solution to expand x^2(1/x-ln(1+1/x)) is x-x^2ln(1+1/x)