What is expand xy''(x)+2y'(x)-(2xy)/((1-x)^2) ?

The solution to expand xy''(x)+2y'(x)-(2xy)/((1-x)^2) is xy''(x)+2y'(x)-(2xy)/(1-2x+x^2)

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expand xy''(x)+2y'(x)-(2xy)/((1-x)^2)

expand

x y^{''} (x) + 2 y^{'} (x) - \frac{2 x y}{( 1 - x ) ^{2}}

x y'' (x) + 2 y' (x) - \frac{2 x y}{1 - 2 x + x ^{2}}

Solution steps

x y^{''} (x) + 2 y^{'} (x) - \frac{2 x y}{( 1 - x ) ^{2}}

(1 - x)^{2} = 1 - 2 x + x^{2}

= x y^{^{''}} (x) + 2 y^{^{'}} (x) - \frac{2 x y}{x ^{2} - 2 x + 1}

\frac{( ( s + 1 ) ^{3} )}{s ^{4}}

\frac{2 + s ^{2}}{s ( s ^{2} + 1 )}

0.2 - (x^{3} - (5 - x)^{3} \cdot 8900 = 0)

\frac{( 9 ( s + 5 ) )}{( ( s + 20 ) ( s + 15 ) )}

\frac{3 x + 11}{( x - 2 ) ^{2}}

What is expand xy''(x)+2y'(x)-(2xy)/((1-x)^2) ?
The solution to expand xy''(x)+2y'(x)-(2xy)/((1-x)^2) is xy''(x)+2y'(x)-(2xy)/(1-2x+x^2)