What is expand ((g+Vsin(θ)k)x)/(kVcos(θ)) ?

The solution to expand ((g+Vsin(θ)k)x)/(kVcos(θ)) is (gx)/(kVcos(θ))+(xsin(θ))/(cos(θ))

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expand ((g+Vsin(θ)k)x)/(kVcos(θ))

expand

\frac{( g + V sin ( θ ) k ) x}{kV cos ( θ )}

\frac{gx}{kV cos ( θ )} + \frac{x sin ( θ )}{cos ( θ )}

Solution steps

\frac{( g + V sin ( θ ) k ) x}{kV cos ( θ )}

Expand

(g + V sin (θ) k) x : gx + kV x sin (θ)

= \frac{gx + kV x sin ( θ )}{kV cos ( θ )}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{gx + kV x sin ( θ )}{kV cos ( θ )} = \frac{gx}{kV cos ( θ )} + \frac{kV x sin ( θ )}{kV cos ( θ )}

= \frac{gx}{kV cos ( θ )} + \frac{kV x sin ( θ )}{kV cos ( θ )}

Cancel

\frac{kV x sin ( θ )}{kV cos ( θ )} : \frac{x sin ( θ )}{cos ( θ )}

= \frac{gx}{kV cos ( θ )} + \frac{x sin ( θ )}{cos ( θ )}

\frac{5 s + 2}{( s + 1 ) ( s + 2 ) ^{2}}

\frac{0.01}{s ( 0.04 s ^{3} + 0.18 s ^{2} + 0.2 s )}

(x^{3} + b + 1)^{3} \cdot x^{2}

\frac{( 2 p + 6 ) p}{2 p + 3}

What is expand ((g+Vsin(θ)k)x)/(kVcos(θ)) ?
The solution to expand ((g+Vsin(θ)k)x)/(kVcos(θ)) is (gx)/(kVcos(θ))+(xsin(θ))/(cos(θ))